Talk:BA Fynn Wawrzyniak
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ConsToPrim(): p(E) < 0
Hilf ein Absenken des initialen Zeitschritts? --Lothar (talk) 07:53, 26 April 2024 (CEST)
Es scheint, dass das Absenken des initialen Zeitschritts nicht hilft. Ich habe einfach mal die logs für verschiedene Einstellung des initialen Zeitschritts beigefügt.
Für \( dt=10^{-10} \)
> Starting computation...
step:0; t = 0.0000e+00; dt = 1.0000e-10; 0.0 %
[Mach = 49.994517]
! ConsToPrim(): p(E) < 0 (-2.34e-05), @step = 66 (stage = 1); [i,j = 2, 73], [x1,x2 = 0.000001, 2.246239]
! ConsToPrim(): p(E) < 0 (-1.27e-05), @step = 66 (stage = 1); [i,j = 2, 74], [x1,x2 = 0.000001, 2.277655]
Für \( dt=10^{-15} \)
> Starting computation...
step:0; t = 0.0000e+00; dt = 1.0000e-15; 0.0 %
[Mach = 49.994517]
step:100; t = 1.3780e-10; dt = 1.3781e-11; 0.0 %
[Mach = 49.995660]
! ConsToPrim(): p(E) < 0 (-3.49e-06), @step = 186 (stage = 2); [i,j = 2, 73], [x1,x2 = 0.000001, 2.246239]
! ConsToPrim(): p(E) < 0 (-1.84e-06), @step = 187 (stage = 1); [i,j = 2, 72], [x1,x2 = 0.000001, 2.214823]
Für \( dt=10^{-20} \)
> Starting computation...
step:0; t = 0.0000e+00; dt = 1.0000e-20; 0.0 %
[Mach = 49.994517]
step:100; t = 1.3780e-15; dt = 1.3781e-16; 0.0 %
[Mach = 49.994517]
step:200; t = 1.8991e-11; dt = 1.8991e-12; 0.0 %
[Mach = 49.994517]
step:300; t = 1.3811e-07; dt = 5.1143e-09; 0.0 %
[Mach = 57.016462]
! ConsToPrim(): p(E) < 0 (-7.80e-06), @step = 307 (stage = 1); [i,j = 2, 73], [x1,x2 = 0.000001, 2.246239]
! ConsToPrim(): p(E) < 0 (-8.17e-06), @step = 307 (stage = 2); [i,j = 2, 73], [x1,x2 = 0.000001, 2.246239]